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Archive for the ‘centripetal acceleration’ Category

February 20, 2015 · by physics · centripetal acceleration, Physics Problem Solver

Question:

A greased pig slides from rest down a frictionless ramp into frictionless circular track of a radius of four meters. What is the magnitude of this centripetal acceleration is it reaches the lowest point? The diagram has the pig starting from a height that eight meters.

Raw Transcript

Hello, everyone. Tom from everystephysics.com and everystepcalculus.com. This is a physics problem. A greased pig slides from rest down a frictionless ramp into frictionless circular track of a radius of four meters. What is the magnitude of this centripetal acceleration is it reaches the lowest point? The diagram has the pig starting from a height that eight meters. So since this asks for centripetal acceleration, we’re gonna go to that in the menu. Physics to get to the main menu. Scroll down to the C section, all alphabetical. I Try to do that in of physics program problems is to search what it has asked for. That would be intelligent way to do it as far as I’m concerned. So we got centripetal acceleration. And you know the formula for that is V squared over R. But there is no V given. No velocity given in the problem. So, because we’re students of engineering or something like that, we have to think a little bit in our own minds. Everything can’t be just handed to us. And so we we need to say what is V and where can we get V. Well, we are going to practice on my program and we would then go. You would get out of the program. You do that by pressing on escape and back home to physics and you choose physics again. And now we choose centripetal velocity. And what we’re given here radius and height in the problem. Choose that. However when height is given, radius is not in the formula. So, we enter the height that’s given. Which is alpha, you have to press alpha before we enter anything into these entry lines, here. Alpha 8 meters. I always show you what you’ve entered, you can change it if you want. I say it’s okay. And the velocity is 12.5 meters per second. The formula is the square root of 2 times gravity times height. And we enter these in here and come up with these calculations. So now we go back to the main menu. Remember that. Write it down, of course. And we’re going to scroll down to centripetal, you can use second to go down screen by screen. Second to get to the menu quicker. And we’re going to choose centripetal acceleration again. We going to enter the initial velocity. Alpha 12.5. That’s meters per second, number 4. We’re going to enter the radius. Alpha 4 meters, number 3. I ask you if it’s okay. And here’s the formula’s. Velocity squared times 4 which is these calculations which is 39.06. And the answer to the problem is 39.1. In a multiple choice problem. So you circle that and you got it perfectly correct. Have a good one.

December 10, 2012 · by physics · centripetal acceleration

Raw Transcript

This is a TI-89 titanium program app for centripetal acceleration and to get to my main menu you have to type in physics press second alpha first and then press alpha to enter the open and close parentheses press enter and you’re into my menu you can see many many things that goes way down
thirty forty items here look you’ll need for physics fluids hydraulics friction path of object strain
stress all kinds of things but today i’m gonna demonstrate acceleration uh… in regards to centripetal
acceleration I’m going to scroll up here to acceleration press enter and then choose number three
centripetal acceleration. I show you the two formulas one is radius times w squared this is speed
angular speed squared and this is v squared over r radius uh… we’re going to enter the cords radius. Let’s say that it’s you have to press alpha before you enter anything in my for my uh… entry lines
and let’s say it’s four point six and I give you the choice of centimeters of meters depends on what’s given in the problem. Let’s say it’s centimeters. I’ll show you how to convert centimeters two meters
you write all this on your paper exactly as you see it to get an a in this problem in physics number of revolutions let’s say it’s three press alpha, three and the choice of revolutions per minute or revolutions per second formula it needs seconds. So I’m going to just I show you what you’ve entered
and you can change it if you want. I say it’s okay. Given the choice of which formally you want to use
let’s do this one here velocity squared velocity equals frequency times two pi times radius and
centripetal acceleration is sixteen point three point four you can use the same variables go back and choose the other formula and same answer. Pretty neat huh? everystepphysics.com. Check out my programs.