Archive for the ‘Physics Videos’ Category
Physics Word Problem Solver
Physics Word Problem: Find dimensions given volume
An open rectangular box has a square base. If the volume must be 32 cubic inches, find the dimensions of the box with minimum surface area.
Question:
A ball is thrown at a 40 degree angle above the horizontal, across level ground. It is released from a height of 2 meters above the ground with the speed of 18 meters per second. What is the height above the ground that the ball reaches?
Raw Transcript
Hello, everyone. Tom from everystepphysics.com and everystepcalculus.com. We’re gonna do a physics problem of a ball being thrown. So I’m going to read it to you. It’s off a test. A ball is thrown at a 40 degree angle above the horizontal, across level ground. It is released from a height of 2 meters above the ground with the speed of 18 meters per second. What is the height above the ground that the ball reaches? It gives you 5 answers. To choose. Multiple choice. So, let’s do it. Physics to get to my menu into the entry line here. And we’re going to scroll down to You can go down the menu quick but this is a long menu so a lot of things in here so you’re going to press second and the cursor second cursor to go down page by page. I did that and went down here we’re going to choose ball thrown. An object launched with angle and initial velocity, it doesn’t make a difference whether it’s a ball or a tennis ball or a rock. Whatever. It’s the same formula’s.So you have to kinda practice with my programs, here to get used how they work. And practice them more than Physics, actually. And I give you the answer here or questions whether it’s aboveground or ground level. It makes a difference. So we’re gonna enter the initial height that they give you.You have to press Alpha before you enter anything into these entry lines, here. Alpha 2 and I always give you choices in case they try to trick you with inches or feet or conversions. We’re going to choose number 2 which is meters. And then the initial velocity is Alpha 18 meters per second, number four. Enter the angle. Alpha 40 degrees. I always show you what you’ve entered so you can change it if you made a mistake. I say it’s okay.
Raw Transcript
Hello, Everyone. Tom from everystepphysics.com and everystepcalculus.com. We’re going to do A Modified Atwood Machine. This time with friction on the table there. And you’ll notice the ninety degree angle. And that angle goes from when the two masses are hanging and he said the pulley that would be zero angle and then up at a table will be ninety degrees so on all the angles in between, I’m always bothered with physics formula’s where they don’t have a complete formula. And it’s not clear. So anyway, the cosine is in the formula and cosine of ninety degrees is zero. So we see how that works. So that’s the only thing to remember that it has an angle and UK also. So we’re gonna get going here. Physics, go to my menu. I’m going to scroll down to Atwood Machine, here. And I’m gonna scroll up to Modified Atwood with theta and UK. I’ll show you a picture in case you didn’t know how to draw it. Now, of course this would be ninety degrees table. I have that in the modified section of this program, also. I’ll show you that. We’re going to put in a mass here. M1 is equal to 5. You have to push Alpha before you enter anything in these entry lines here. So it’s Alpha 5 kilograms and then M2 is Alpha 11 kilograms. Theta then would be ninety degrees and UK would be point 8 as it’s given. I always show you which have entered, you can change it if you want. I say it’s okay. Here’s the formula. Notice UK’s in the second part of this equation. All divided by the total masses. And then we have cosine here. They enter the variables. And here’s the answer: 6.744 meters per squared. You notice how the second term of this formula became 0 because cosine of ninety is 0. Pretty neat, huh? everystepphysics.com and everystepcalculus.com. Go to my site, buy my program, pass your classes, and subscribe if you wanna see more movies. I also give tension here. See the tension because tension uses the acceleration that we found previous. Have a good day!
A cart is given an initial velocity of 5 meters per second and experiences a constant acceleration of 2 meters per second squared. What is the magnitude of the carts displacement during the first six seconds of it’s motion?
Raw Transcript
Hello, Everyone. Tom from everystephysics.com. Here’s a test problem. I’m gonna read for you. A cart is given an initial velocity of 5 meters per second and experiences a constant acceleration of 2 meters per second squared. What is the magnitude of the carts displacement during the first six seconds of it’s motion? I always want you to in these problems to circle what’s asked for. In this case displacement and I want you to write on the side of the program what’s given. Which is in this case initial velocity, acceleration, and time. So, let’s the do it. You have to put physics in here with the open/close parentheses to get my menu. We’re gonna scroll down to displacement because that’s what it’s asked for. And we’re gonna choose what’s given which is velocity, acceleration, and time. There’s a formula for it. You have to press Alpha before you enter anything in these entry lines. So the the initial velocity is Alpha five and meters per second. I do the conversions. Is acceleration given? Yes. Acceleration alpha 2. And the time is alpha 6. I always show you what you’ve entered. You can change it if you want. I say it’s okay. Here’s the answer: letter C
A rock is thrown straight down with an Initial Velocity a 14.5 meters per second, from a cliff. What is the rocks displacement after two seconds? Acceleration due to gravity is 9.8 meters per second squared.
Raw Transcript
Hello, Everyone. Tom from everystepphysics.com I’m going to read a test problem to you. A rock is thrown straight down with an Initial Velocity a 14.5 meters per second, from a cliff. What is the rocks displacement after two seconds? Acceleration due to gravity is 9.8 meters per second squared. So let’s get started. Physics to get my menu. Scroll down to Displacement because that’s what you’ve circled. And that’s what is asked for the problem. And we scroll to what’s given and in this case velocity. Initial velocity, time, and acceleration. There’s a formula. Write that on your paper. And you have to press Alpha before enter anything in here. So we have to press Alpha. Initial Velocity is 14.5 meters per second. Is acceleration given? It is but in case it wasn’t, I’m going to show you this, you can put 9.81 in there but if you didn’t, it’s assumed that you’re supposed to know that. So I’m going to choose number 2. It goes right away to time. Alpha is two seconds. And I always show you what you’ve entered so you can change it if you want. I say it’s okay. Here’s the answer: 48.6 And they have for their answer 49 when they here for their answer 49. You’d circle that one and get an A on this problem. Pretty neat, huh? everystepphysics.com Go to my site, buy my programs, and subscribe. Thank you
A cart is given an initial velocity 5 meters per second and experience’s a constant acceleration a two meters per second square. What is the magnitude of the carts displacement during the first six seconds of its motion?
Raw Transcript
Hello, Everyone. Tom from everystepphysics.com Here’s a test problem. I’m going to read it for you. A cart is given an initial velocity 5 meters per second and experience’s is a constant acceleration a two meters per second square. What is the magnitude of the carts displacement during the first six seconds of its motion? I always want you to in these problems to circle what’s ask for. In this case displacement and I want you to write on the side of the program what’s given. Which is in this case initial velocity acceleration in time. So let’s do it. Put physics in here with the open/close parentheses to get to my menu. We’re going to scroll down to displacement because that’s what it asks for. I’m going to choose what’s given which is velocity acceleration in time. There’s a formula for it. You have to press Alpha before we enter anything into the entry lines. So the initial velocity is Alpha five and meters per second. I do the conversions. Is acceleration given? Yes. Acceleration Alpha 2. And the time is Alpha 6. I always show you what you’ve entered. You can change it if you want. I say okay. Here’s the answer. Letter C, on the test. Pretty neat, huh? everystepphysics.com Go to my site, buy my programs and subscribe to me so you can see more movies. Thank you
A ball rolls horizontally off the edge of a tabletop that is 19.6 meters high. It strikes the ground at a point 6 meters from the edge of the table.
a) How long was it in the air?
b) What was its speed at the instant it left the table?
Raw Transcript
Hello everyone, this is Tom from everystepphysics.com. We’re gonna do a problem that was is in a test and asked from a customer. And relating to path of objects. So, let’s get started. Physics is my key to put in this entry line here in the calculator. To get my menu, you press enter and we’re already at path of objects.
You can see pressure, pressure gauge,pulley, radius, roller coaster; all kinds of things in this menu.
for you to pass your physics test. Path of objects. I gave you three choices. Notice that there’s they ask if they’re angle or if the velocity is given or neither is given. In this case, neither was given. So we’re gonna choose number three. You can scroll down to it or you can press the number before and I like the press the number before. And a course they gave me the the height. His ball is rolling off a table and height of the table is… We have to press alpha before you enter anything in these entry lines here. The height is
Alpha 19.6 You always put that in and I always ask you or give you the choice of what they have entered sometimes you’ll enter inches or feet, or anything. It all changes to meters and in this case meters so we’re going to choose number two. And then the distance along the ground. They say this ball drop 6 meters from the edge in the table. We’re going to press alpha 6 meters. Seemingly a simple problem isn’t it, huh? Initial Heights thats i, initial height, that’s 19.6 meters and the distance is from the table is equal to 6 meters. I’ll show you what you’ve entered so you can change it if you want. I say it’s okay. And they ask you to find the time in a air. Well, that’s the time to the ground 1.999 seconds. Basically two seconds to the ground. here’s the exact equations here. You have to find that before you can find the initial speed. Remember speed is absolute, in other words, you can’t be negative. Velocity is a vector can be negative or positive and shows direction and magnitude. Speed shows magnitude but doesn’t show any direction, etc. And of course the ball rolling off the table has to be plus, can’t be minus. And so the answer is 6.8
meters per second. Pretty neat, huh? everystepphysics.com, go to my site, buy my program and pass your physics class. Very difficult classes. And also subscribe to me so you can see future videos and blog.
Physics Help Online with the TI-89 Calculator: Video Transcript
This is a video from every step physics dot com demonstrating how my programs work with the t i 89 titanium calculator and other calculators in the t i system for physics and calculus problems ah this is better than physics help on line because you download the programs right into you calculator and you have all the help you need ah for what I’ve programmed which is quite a bit and let’s get started on how they work you press second alpha to put p h y s i c s in the entry line of the calculator press alpha to put the open and closed parenthesis press enter and you’re into my menu
many things here for your help on line whatever you have to
choose what you want and uhm do center of mass here
ah here’s the formula center of mass is the
sums of these ecetera and I give you the choice of
two masses or two masses in the x y plane
three masses x axis three masses x y plane
four masses x y plane let’s do number four
three masses in x y plane first mass
you have to put alpha before you enter anything into the entry
lines of my programs here alpha eight first mass
we’ll say it’s kilograms I give you that choice though
alpha twelve kilograms
and here’s the third one alpha six kilograms
first coordinate x equals four
meters second coordinate
the y alpha
let’s go minus six meters
second coordinate for the x value alpha seven
meters and then the y value
alpha minus four meters third coordinate
alpha seven meters alpha six meters
I show you the whole thing that you’ve entered so you can
change it if you want if you’ve made a mistake
we’ll say it’s ok and you’re doing the sums of these
remember and here’s the calculations
write everything down on your paper just as you see it
like you’re doing the calculations yourself center of mass is six point zero eight meters
and the x y z is equal to six point zero eight zero zero
pretty neat huh every step physics dot com
go to my site buy my programs
and pass your physics
Bullet Hits Steel Plate on TI-89: Raw Transcript
This is a video from every step physics dot com
demonstrating how my program work on the TI-89 Titanium calculator
and other calculators in the TI system for physics and calculus problems
here’s a problem that is on many tests in physics
and ah if a bullet traveling at three hunderd fifty
meters per second strikes a steel plate
at an angle of 30 degrees as shown It recochets off
with the same angle at a speed of three hundred twenty meters
per second what is the magnitude of the impulse that
the plate gives the bullet
and in my programs ah you
find first what the problem is asking in this case it’s asking impulse
and you go to my menu and you scroll down for impulse
and then you on the side of your problem
instead of looking at it or thinking about the problem at all you just
put what’s given here which is mass
twenty grams and initial velocity
which is three hundred fifty meters per second final velocity would be
three hundred twenty meters per second and then a thirty degree angle
and here’s the picture of what’s happening and this is really vector addition
so let’s get started here ah you have to press second alpha
to put these letters in here to get to my program menu
p h y s i c s and then you have to press alpha again
to put the open and closed parenthesis and press enter and you are into my menu
I’ve scrolled down to impulse here to save some time
but you start it brings you to the top of the menu
and then you have all these other choices and uhm
we get to impulse we press enter
gives you these variables here for impulse
and right now in this problem we want the mass
the initial velocity the final velocity
and the angle we choose that
we enter your variables you have to press alpha first
before we enter any variables into the entry lines of my programs
so were going to press alpha and put down
put in twenty it also might give you kilograms or grams
in this case it gives you the bullet as grams so I’m going to put that there
it shows you you take twent and divide it by a thousand
to get point zero two kilograms which is necessary for the formula
and the initial velocity your going to press alpha
and put in three fifty that’s the way the bullet is traveling
and it’s not in centimeters it’s in meters
so were going to choose number two you can press or scroll to that choice
final velocity alpha three twenty
meters again per second and then the angle is
alpha thirty I always show you what you’ve entered
so you can change it this looks good to me
it’s been changed from grams to kilograms etcetera
and this is vector addition who would have known that
if you just saw a problem in a test ah here’s the impulse vector resultant
ah the square root of the x axis and y axis
and the I of the impulse and here’s the formula
and then we add the the all the variables
you write this on paper you don’t think about it
and the I y is six point seven newtons second
and the answer is six point seven two three one
newtons second pretty neat huh
EveryStepPhysics.com go to my site
buy my programs and pass physics
Buy Now: $29.95
.
.