Question:

A ball is thrown at a 40 degree angle above the horizontal, across level ground. It is released from a height of 2 meters above the ground with the speed of 18 meters per second. What is the height above the ground that the ball reaches?

Raw Transcript

Hello, everyone. Tom from everystepphysics.com and everystepcalculus.com. We’re gonna do a physics problem of a ball being thrown. So I’m going to read it to you. It’s off a test. A ball is thrown at a 40 degree angle above the horizontal, across level ground. It is released from a height of 2 meters above the ground with the speed of 18 meters per second. What is the height above the ground that the ball reaches? It gives you 5 answers. To choose. Multiple choice. So, let’s do it. Physics to get to my menu into the entry line here. And we’re going to scroll down to You can go down the menu quick but this is a long menu so a lot of things in here so you’re going to press second and the cursor second cursor to go down page by page. I did that and went down here we’re going to choose ball thrown. An object launched with angle and initial velocity, it doesn’t make a difference whether it’s a ball or a tennis ball or a rock. Whatever. It’s the same formula’s.So you have to kinda practice with my programs, here to get used how they work. And practice them more than Physics, actually. And I give you the answer here or questions whether it’s aboveground or ground level. It makes a difference. So we’re gonna enter the initial height that they give you.You have to press Alpha before you enter anything into these entry lines, here. Alpha 2 and I always give you choices in case they try to trick you with inches or feet or conversions. We’re going to choose number 2 which is meters. And then the initial velocity is Alpha 18 meters per second, number four. Enter the angle. Alpha 40 degrees. I always show you what you’ve entered so you can change it if you made a mistake. I say it’s okay.